Y=0.625x^2+5x

Solution for Y=0.625x^2+5x equation:

=0.625Y^2+5Y

We move all terms to the left:

-(0.625Y^2+5Y)=0

We get rid of parentheses

-0.625Y^2-5Y=0

a = -0.625; b = -5; c = 0;
Δ = b2-4ac
Δ = -52-4·(-0.625)·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5}{2*-0.625}=\frac{0}{-1.25}
=0
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5}{2*-0.625}=\frac{10}{-1.25}
=-8
$